The Voltage Divider Lab

1) Do not build this project circuit unless you have a volt meter to verity your voltage readings.
2) Do not leave this circuit connected for an extended period of time as it will discharge the battery.
Build this experiment, following the instructions that accompany the kit.
Review the Resistor Color Code chart and wire up the kit as described.
Perform the lab, and record your results.

....Parts layout:
Parts List:
1 9-volt battery
1 Battery power clip
6 1k ohm resistors - R1, R2, R3, R4, R5, R6 (brown, black, red)
1 experimenters board
hookup wire

Short Circuit and Open Circuit

A short circuit is when a section of a circuit fails due to a component having much lower then expected or zero resistance. A short circuit can be simulated by placing a wire jumper across a component. Many times circuits are not designed to allow shorts so creating one is a poor idea.
In this book I have designed a few safe circuits where we will experiment with planned short circuits We will use this concept to replace a switch as we move along in the book.

Open circuits occur causing a circuit fails to work properly because a component does not behave as if it is in a circuit. The component is called open.

In this section you will start building your trouble shooting skills. You can either just run through the math or you can use the Work Bench trainer and substitute R6 and measure the results as indicated in the problems. Either way we will be using the combination circuit just discussed.

If R6 became a short circuit, or zero ohms on the diagram.
On the trainer, remove R6 and replace it with the jumper wire.

Find new voltage at Point A.
Find new voltage at Point B.
Find new voltage at Point C.

If R6 became an open circuit or just remove it from the diagram.
On the trainer, remove R6 or the jumper wire that replaced
R6 in the previous question.

Find new voltage at Point A.
Find new voltage at Point B.
Find new voltage at Point C.

Simple Voltage Divider

A voltage divider can be a simple series circuit that divides up the supply voltage (potential) into one or more lower levels of voltage (potential).
In an earlier example we had a 9 volt battery and two series resistors.
In this section, we have a longer voltage divider. In the schematic drawing, Point A is the circuit common point. It is at some point mid way between the plus and minus terminals of the battery. This divider provides both positive voltage and negative voltage points within the same circuit. From Point A which in common, voltages at Point B and Point C will be more positive than Point A. Point D and Point E will be more negative to Point A.

Given: 30 volt supply
R1: 60 ohms
R2: 60 ohms
R3: 240 ohms
R4: 100 ohms
R5: 140 ohms

Calculate the voltage, with respect to Point A for:
Point B
Point C
Point D
Point E

Total series resistance is: (60+60+240+100+140) = 600 ohms
Total series current is I = E / R or ( 30 / 600 ) or 0.05 amps
Point B = voltage across R2 and R3: E = I X R
work: E = ( 0.05 X 300 ) = 15 volts at Point B

Point C = voltage across R3: E = I X R
work: E = ( 0.05 X 240 ) = 12 volts at Point C

Point D = voltage across R4: E = I X R (minus voltage)
work: E = ( 0.05 X 100 ) = -5 volts at Point D

Point E = voltage across R4 and R5: E = I X R (minus voltage)
work: E = ( 0.05 X 240 ) = -12 volts at Point E

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